3.131 \(\int \frac {\sqrt {a+a \cosh (x)}}{x^2} \, dx\)

Optimal. Leaf size=42 \[ \frac {1}{2} \text {Shi}\left (\frac {x}{2}\right ) \text {sech}\left (\frac {x}{2}\right ) \sqrt {a \cosh (x)+a}-\frac {\sqrt {a \cosh (x)+a}}{x} \]

[Out]

-(a+a*cosh(x))^(1/2)/x+1/2*sech(1/2*x)*Shi(1/2*x)*(a+a*cosh(x))^(1/2)

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Rubi [A]  time = 0.09, antiderivative size = 42, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 3, integrand size = 14, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.214, Rules used = {3319, 3297, 3298} \[ \frac {1}{2} \text {Shi}\left (\frac {x}{2}\right ) \text {sech}\left (\frac {x}{2}\right ) \sqrt {a \cosh (x)+a}-\frac {\sqrt {a \cosh (x)+a}}{x} \]

Antiderivative was successfully verified.

[In]

Int[Sqrt[a + a*Cosh[x]]/x^2,x]

[Out]

-(Sqrt[a + a*Cosh[x]]/x) + (Sqrt[a + a*Cosh[x]]*Sech[x/2]*SinhIntegral[x/2])/2

Rule 3297

Int[((c_.) + (d_.)*(x_))^(m_)*sin[(e_.) + (f_.)*(x_)], x_Symbol] :> Simp[((c + d*x)^(m + 1)*Sin[e + f*x])/(d*(
m + 1)), x] - Dist[f/(d*(m + 1)), Int[(c + d*x)^(m + 1)*Cos[e + f*x], x], x] /; FreeQ[{c, d, e, f}, x] && LtQ[
m, -1]

Rule 3298

Int[sin[(e_.) + (Complex[0, fz_])*(f_.)*(x_)]/((c_.) + (d_.)*(x_)), x_Symbol] :> Simp[(I*SinhIntegral[(c*f*fz)
/d + f*fz*x])/d, x] /; FreeQ[{c, d, e, f, fz}, x] && EqQ[d*e - c*f*fz*I, 0]

Rule 3319

Int[((c_.) + (d_.)*(x_))^(m_.)*((a_) + (b_.)*sin[(e_.) + (f_.)*(x_)])^(n_), x_Symbol] :> Dist[((2*a)^IntPart[n
]*(a + b*Sin[e + f*x])^FracPart[n])/Sin[e/2 + (a*Pi)/(4*b) + (f*x)/2]^(2*FracPart[n]), Int[(c + d*x)^m*Sin[e/2
+ (a*Pi)/(4*b) + (f*x)/2]^(2*n), x], x] /; FreeQ[{a, b, c, d, e, f, m}, x] && EqQ[a^2 - b^2, 0] && IntegerQ[n
+ 1/2] && (GtQ[n, 0] || IGtQ[m, 0])

Rubi steps

\begin {align*} \int \frac {\sqrt {a+a \cosh (x)}}{x^2} \, dx &=\left (\sqrt {a+a \cosh (x)} \text {sech}\left (\frac {x}{2}\right )\right ) \int \frac {\cosh \left (\frac {x}{2}\right )}{x^2} \, dx\\ &=-\frac {\sqrt {a+a \cosh (x)}}{x}+\frac {1}{2} \left (\sqrt {a+a \cosh (x)} \text {sech}\left (\frac {x}{2}\right )\right ) \int \frac {\sinh \left (\frac {x}{2}\right )}{x} \, dx\\ &=-\frac {\sqrt {a+a \cosh (x)}}{x}+\frac {1}{2} \sqrt {a+a \cosh (x)} \text {sech}\left (\frac {x}{2}\right ) \text {Shi}\left (\frac {x}{2}\right )\\ \end {align*}

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Mathematica [A]  time = 0.05, size = 33, normalized size = 0.79 \[ \frac {\sqrt {a (\cosh (x)+1)} \left (x \text {Shi}\left (\frac {x}{2}\right ) \text {sech}\left (\frac {x}{2}\right )-2\right )}{2 x} \]

Antiderivative was successfully verified.

[In]

Integrate[Sqrt[a + a*Cosh[x]]/x^2,x]

[Out]

(Sqrt[a*(1 + Cosh[x])]*(-2 + x*Sech[x/2]*SinhIntegral[x/2]))/(2*x)

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fricas [F(-2)]  time = 0.00, size = 0, normalized size = 0.00 \[ \text {Exception raised: TypeError} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((a+a*cosh(x))^(1/2)/x^2,x, algorithm="fricas")

[Out]

Exception raised: TypeError >>  Error detected within library code:   integrate: implementation incomplete (ha
s polynomial part)

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giac [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {\sqrt {a \cosh \relax (x) + a}}{x^{2}}\,{d x} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((a+a*cosh(x))^(1/2)/x^2,x, algorithm="giac")

[Out]

integrate(sqrt(a*cosh(x) + a)/x^2, x)

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maple [F]  time = 0.09, size = 0, normalized size = 0.00 \[ \int \frac {\sqrt {a +a \cosh \relax (x )}}{x^{2}}\, dx \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((a+a*cosh(x))^(1/2)/x^2,x)

[Out]

int((a+a*cosh(x))^(1/2)/x^2,x)

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maxima [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {\sqrt {a \cosh \relax (x) + a}}{x^{2}}\,{d x} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((a+a*cosh(x))^(1/2)/x^2,x, algorithm="maxima")

[Out]

integrate(sqrt(a*cosh(x) + a)/x^2, x)

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mupad [F]  time = 0.00, size = -1, normalized size = -0.02 \[ \int \frac {\sqrt {a+a\,\mathrm {cosh}\relax (x)}}{x^2} \,d x \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((a + a*cosh(x))^(1/2)/x^2,x)

[Out]

int((a + a*cosh(x))^(1/2)/x^2, x)

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sympy [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {\sqrt {a \left (\cosh {\relax (x )} + 1\right )}}{x^{2}}\, dx \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((a+a*cosh(x))**(1/2)/x**2,x)

[Out]

Integral(sqrt(a*(cosh(x) + 1))/x**2, x)

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